What are the solutions to the equation -3(x+5)^2=12 ?

The solutions to the equation -3(x+5)^2=12 are x=2i-5,x=-2i-5

Find the zeros of -3(x+5)^2=12

The zeros of -3(x+5)^2=12 are x=2i-5,x=-2i-5

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- 3 (x + 5)^{2} = 12

x = 2 i - 5, x = - 2 i - 5

Solution steps

- 3 (x + 5)^{2} = 12

Divide both sides by

- 3

(x + 5)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = - 4 : x = 2 i - 5

Solve

x + 5 = - - 4 : x = - 2 i - 5

The solutions to the quadratic equation are:

x = 2 i - 5, x = - 2 i - 5

x, x^{2} - 2 x - 2 = 0

3 s^{2} + 18 s + 14 = 0

x, z = x^{2} y + 1

A, A BX A - 1 B - 1 = I + A

(x + 3)^{2} - (x - 3)^{2} = x^{2} + 32

What are the solutions to the equation -3(x+5)^2=12 ?
The solutions to the equation -3(x+5)^2=12 are x=2i-5,x=-2i-5
Find the zeros of -3(x+5)^2=12
The zeros of -3(x+5)^2=12 are x=2i-5,x=-2i-5