What are the solutions to the equation 3x^2+10x+9=-3x+5 ?

The solutions to the equation 3x^2+10x+9=-3x+5 are x=-1/3 ,x=-4

Find the zeros of 3x^2+10x+9=-3x+5

The zeros of 3x^2+10x+9=-3x+5 are x=-1/3 ,x=-4

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3 x^{2} + 10 x + 9 = - 3 x + 5

x = - \frac{1}{3}, x = - 4

Decimal Notation

x = - 0.33333 \dots, x = - 4

Solution steps

3 x^{2} + 10 x + 9 = - 3 x + 5

Move

5

to the left side

3 x^{2} + 10 x + 4 = - 3 x

Move

3 x

to the left side

3 x^{2} + 13 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 \cdot 4 = 11

x_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 13 + 11}{2 \cdot 3}, x_{2} = \frac{- 13 - 11}{2 \cdot 3}

x = \frac{- 13 + 11}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 13 - 11}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 4

6 0^{2} + 1 1^{2} = x^{2}

x, x y^{2} + x^{2} y = 2

6 x^{2} - 8 = 52

(2 x + 3) (5 x - 1) = 0

x^{2} + 11 x - 26 = 4 x - 8

What are the solutions to the equation 3x^2+10x+9=-3x+5 ?
The solutions to the equation 3x^2+10x+9=-3x+5 are x=-1/3 ,x=-4
Find the zeros of 3x^2+10x+9=-3x+5
The zeros of 3x^2+10x+9=-3x+5 are x=-1/3 ,x=-4