What are the solutions to the equation x^2+11x-26=4x-8 ?

The solutions to the equation x^2+11x-26=4x-8 are x=2,x=-9

Find the zeros of x^2+11x-26=4x-8

The zeros of x^2+11x-26=4x-8 are x=2,x=-9

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x^{2} + 11 x - 26 = 4 x - 8

x = 2, x = - 9

Solution steps

x^{2} + 11 x - 26 = 4 x - 8

Move

8

to the left side

x^{2} + 11 x - 18 = 4 x

Move

4 x

to the left side

x^{2} + 7 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 18) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 1}, x_{2} = \frac{- 7 - 11}{2 \cdot 1}

x = \frac{- 7 + 11}{2 \cdot 1} : 2

x = \frac{- 7 - 11}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 2, x = - 9

- a^{2} - a = 0

3 x^{2} - 8 x + 10 = 0

2^{1} - x^{2} = \frac{1}{8}

3 x^{2} - 2 = - 8

84 x^{2} - 12 = 0

What are the solutions to the equation x^2+11x-26=4x-8 ?
The solutions to the equation x^2+11x-26=4x-8 are x=2,x=-9
Find the zeros of x^2+11x-26=4x-8
The zeros of x^2+11x-26=4x-8 are x=2,x=-9