What are the solutions to the equation -a^2-a=0 ?

The solutions to the equation -a^2-a=0 are a=-1,a=0

Find the zeros of -a^2-a=0

The zeros of -a^2-a=0 are a=-1,a=0

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- a^{2} - a = 0

a = - 1, a = 0

Solution steps

- a^{2} - a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 0 = 1

a_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 ( - 1 )}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 1}{2 ( - 1 )}, a_{2} = \frac{- ( - 1 ) - 1}{2 ( - 1 )}

a = \frac{- ( - 1 ) + 1}{2 ( - 1 )} : - 1

a = \frac{- ( - 1 ) - 1}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

a = - 1, a = 0

3 x^{2} - 8 x + 10 = 0

2^{1} - x^{2} = \frac{1}{8}

3 x^{2} - 2 = - 8

84 x^{2} - 12 = 0

x^{2} - 14 x + 49 = 5

What are the solutions to the equation -a^2-a=0 ?
The solutions to the equation -a^2-a=0 are a=-1,a=0
Find the zeros of -a^2-a=0
The zeros of -a^2-a=0 are a=-1,a=0