What are the solutions to the equation x^2-14x+49=5 ?

The solutions to the equation x^2-14x+49=5 are x=7+sqrt(5),x=7-sqrt(5)

Find the zeros of x^2-14x+49=5

The zeros of x^2-14x+49=5 are x=7+sqrt(5),x=7-sqrt(5)

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x^{2} - 14 x + 49 = 5

x = 7 + 5, x = 7 - 5

Decimal Notation

x = 9.23606 \dots, x = 4.76393 \dots

Solution steps

x^{2} - 14 x + 49 = 5

Move

5

to the left side

x^{2} - 14 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 44 = 25

x_{1, 2} = \frac{- ( - 14 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 5}{2 \cdot 1} : 7 + 5

x = \frac{- ( - 14 ) - 2 5}{2 \cdot 1} : 7 - 5

The solutions to the quadratic equation are:

x = 7 + 5, x = 7 - 5

x^{2} + 89 = 19 x - 1

- x^{2} + 2 x = 8

8 n^{2} = 64 n

(3 x + 10)^{2} + 81 = 0

x, 500 \cdot x^{2} - (500 \cdot x) = 1000

What are the solutions to the equation x^2-14x+49=5 ?
The solutions to the equation x^2-14x+49=5 are x=7+sqrt(5),x=7-sqrt(5)
Find the zeros of x^2-14x+49=5
The zeros of x^2-14x+49=5 are x=7+sqrt(5),x=7-sqrt(5)