What are the solutions to the equation 600=-q^2+1000 ?

The solutions to the equation 600=-q^2+1000 are q=20,q=-20

Find the zeros of 600=-q^2+1000

The zeros of 600=-q^2+1000 are q=20,q=-20

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600 = - q^{2} + 1000

q = 20, q = - 20

Solution steps

600 = - q^{2} + 1000

Switch sides

- q^{2} + 1000 = 600

Move

1000

to the right side

- q^{2} = - 400

Divide both sides by

- 1

q^{2} = 400

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 400, q = - 400

400 = 20

- 400 = - 20

q = 20, q = - 20

x^{2} - \frac{2}{5} x + \frac{1}{25} = 0

r^{2} - 9 r + 20 = 0

- 4 x^{2} - 12 x + 10 = 0

x, 11 x^{2} - 24 x y + 4 y^{2} + 20 = 0

x, x^{2} y - x^{2} - 4 x y + 4 y = 0

What are the solutions to the equation 600=-q^2+1000 ?
The solutions to the equation 600=-q^2+1000 are q=20,q=-20
Find the zeros of 600=-q^2+1000
The zeros of 600=-q^2+1000 are q=20,q=-20