What are the solutions to the equation r^2-9r+20=0 ?

The solutions to the equation r^2-9r+20=0 are r=5,r=4

Find the zeros of r^2-9r+20=0

The zeros of r^2-9r+20=0 are r=5,r=4

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r^{2} - 9 r + 20 = 0

r = 5, r = 4

Solution steps

r^{2} - 9 r + 20 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

r_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, r_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

r = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

r = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

r = 5, r = 4

- 4 x^{2} - 12 x + 10 = 0

x, 11 x^{2} - 24 x y + 4 y^{2} + 20 = 0

x, x^{2} y - x^{2} - 4 x y + 4 y = 0

2 - 3 x^{2} = 2^{2} + 2 x^{2}

8 x^{2} + 3 x + 6 = 0

What are the solutions to the equation r^2-9r+20=0 ?
The solutions to the equation r^2-9r+20=0 are r=5,r=4
Find the zeros of r^2-9r+20=0
The zeros of r^2-9r+20=0 are r=5,r=4