What are the solutions to the equation 8x^2+3x+6=0 ?

The solutions to the equation 8x^2+3x+6=0 are x=-3/16+i(sqrt(183))/(16),x=-3/16-i(sqrt(183))/(16)

Find the zeros of 8x^2+3x+6=0

The zeros of 8x^2+3x+6=0 are x=-3/16+i(sqrt(183))/(16),x=-3/16-i(sqrt(183))/(16)

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8 x^{2} + 3 x + 6 = 0

x = - \frac{3}{16} + i \frac{183}{16}, x = - \frac{3}{16} - i \frac{183}{16}

Solution steps

8 x^{2} + 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 8 \cdot 6}{2 \cdot 8}

Simplify

3^{2} - 4 \cdot 8 \cdot 6 : 183 i

x_{1, 2} = \frac{- 3 \pm 183 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 3 + 183 i}{2 \cdot 8}, x_{2} = \frac{- 3 - 183 i}{2 \cdot 8}

x = \frac{- 3 + 183 i}{2 \cdot 8} : - \frac{3}{16} + i \frac{183}{16}

x = \frac{- 3 - 183 i}{2 \cdot 8} : - \frac{3}{16} - i \frac{183}{16}

The solutions to the quadratic equation are:

x = - \frac{3}{16} + i \frac{183}{16}, x = - \frac{3}{16} - i \frac{183}{16}

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x, 16 x^{2} - 9 y^{2} - 64 x - 18 y + E = 0

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What are the solutions to the equation 8x^2+3x+6=0 ?
The solutions to the equation 8x^2+3x+6=0 are x=-3/16+i(sqrt(183))/(16),x=-3/16-i(sqrt(183))/(16)
Find the zeros of 8x^2+3x+6=0
The zeros of 8x^2+3x+6=0 are x=-3/16+i(sqrt(183))/(16),x=-3/16-i(sqrt(183))/(16)