What are the solutions to the equation (2x-5)(3x-1)=0 ?

The solutions to the equation (2x-5)(3x-1)=0 are x= 5/2 ,x= 1/3

Find the zeros of (2x-5)(3x-1)=0

The zeros of (2x-5)(3x-1)=0 are x= 5/2 ,x= 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 5) (3 x - 1) = 0

x = \frac{5}{2}, x = \frac{1}{3}

Decimal Notation

x = 2.5, x = 0.33333 \dots

Solution steps

(2 x - 5) (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or 3 x - 1 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{1}{3}

6 x^{2} + 18 x + 6 = 0

x, 16 x^{2} - 9 y^{2} - 64 x - 18 y + E = 0

A (x) = x^{2} + \frac{1.7}{4} (\frac{2}{3} - \frac{4}{3} x)^{2}

2 x^{2} - 180 x + 400 = 0

(2 x + 5) (3 x - 2) = (x + 1)

What are the solutions to the equation (2x-5)(3x-1)=0 ?
The solutions to the equation (2x-5)(3x-1)=0 are x= 5/2 ,x= 1/3
Find the zeros of (2x-5)(3x-1)=0
The zeros of (2x-5)(3x-1)=0 are x= 5/2 ,x= 1/3