What are the solutions to the equation z^2-2z-24=0 ?

The solutions to the equation z^2-2z-24=0 are z=6,z=-4

Find the zeros of z^2-2z-24=0

The zeros of z^2-2z-24=0 are z=6,z=-4

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z^{2} - 2 z - 24 = 0

z = 6, z = - 4

Solution steps

z^{2} - 2 z - 24 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

z_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, z_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

z = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

z = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

z = 6, z = - 4

(x^{2} - x + 2) = 0

x^{2} - 8 x + 8 = - 4 - 4

3 - 5 x - 2 x^{2} = 0

b^{2} x^{2} - b x = 30

9 + c^{2} = 25

What are the solutions to the equation z^2-2z-24=0 ?
The solutions to the equation z^2-2z-24=0 are z=6,z=-4
Find the zeros of z^2-2z-24=0
The zeros of z^2-2z-24=0 are z=6,z=-4