What are the solutions to the equation 3-5x-2x^2=0 ?

The solutions to the equation 3-5x-2x^2=0 are x=-3,x= 1/2

Find the zeros of 3-5x-2x^2=0

The zeros of 3-5x-2x^2=0 are x=-3,x= 1/2

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3 - 5 x - 2 x^{2} = 0

x = - 3, x = \frac{1}{2}

Decimal Notation

x = - 3, x = 0.5

Solution steps

3 - 5 x - 2 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 3 = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 7}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 7}{2 ( - 2 )} : - 3

x = \frac{- ( - 5 ) - 7}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - 3, x = \frac{1}{2}

b^{2} x^{2} - b x = 30

9 + c^{2} = 25

x^{2} - 4 (x + 3)^{2} - 12 = 0

a, 4 a - 2 a^{2} = 4 b - 2 b^{2}

x^{2} + 14 x - 51 = 0

What are the solutions to the equation 3-5x-2x^2=0 ?
The solutions to the equation 3-5x-2x^2=0 are x=-3,x= 1/2
Find the zeros of 3-5x-2x^2=0
The zeros of 3-5x-2x^2=0 are x=-3,x= 1/2