What are the solutions to the equation solvefor a,4a-2a^2=4b-2b^2 ?

The solutions to the equation solvefor a,4a-2a^2=4b-2b^2 are a=-b+2,a=b

Find the zeros of solvefor a,4a-2a^2=4b-2b^2

The zeros of solvefor a,4a-2a^2=4b-2b^2 are a=-b+2,a=b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

a, 4 a - 2 a^{2} = 4 b - 2 b^{2}

a = - b + 2, a = b

Solution steps

4 a - 2 a^{2} = 4 b - 2 b^{2}

Move

2 b^{2}

to the left side

4 a - 2 a^{2} + 2 b^{2} = 4 b

Move

4 b

to the left side

4 a - 2 a^{2} + 2 b^{2} - 4 b = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 a^{2} + 4 a + 2 b^{2} - 4 b = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( 2 b ^{2} - 4 b )}{2 ( - 2 )}

Simplify

4^{2} - 4 (- 2) (2 b^{2} - 4 b) : 4 (b - 1)

a_{1, 2} = \frac{- 4 \pm 4 ( b - 1 )}{2 ( - 2 )}

Separate the solutions

a_{1} = \frac{- 4 + 4 ( b - 1 )}{2 ( - 2 )}, a_{2} = \frac{- 4 - 4 ( b - 1 )}{2 ( - 2 )}

a = \frac{- 4 + 4 ( b - 1 )}{2 ( - 2 )} : - b + 2

a = \frac{- 4 - 4 ( b - 1 )}{2 ( - 2 )} : b

The solutions to the quadratic equation are:

a = - b + 2, a = b

x^{2} + 14 x - 51 = 0

5 x^{2} + (2 n - 3) x + 2001 = 0

7 x^{2} = - 7 (x + 1)

x^{2} + 5 x - 18 = 0

- x^{2} + 5 x + 8 = 0

What are the solutions to the equation solvefor a,4a-2a^2=4b-2b^2 ?
The solutions to the equation solvefor a,4a-2a^2=4b-2b^2 are a=-b+2,a=b
Find the zeros of solvefor a,4a-2a^2=4b-2b^2
The zeros of solvefor a,4a-2a^2=4b-2b^2 are a=-b+2,a=b