What are the solutions to the equation x^2+5x-18=0 ?

The solutions to the equation x^2+5x-18=0 are x=(-5+sqrt(97))/2 ,x=(-5-sqrt(97))/2

Find the zeros of x^2+5x-18=0

The zeros of x^2+5x-18=0 are x=(-5+sqrt(97))/2 ,x=(-5-sqrt(97))/2

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x^{2} + 5 x - 18 = 0

x = \frac{- 5 + 97}{2}, x = \frac{- 5 - 97}{2}

Decimal Notation

x = 2.42442 \dots, x = - 7.42442 \dots

Solution steps

x^{2} + 5 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 18) = 97

x_{1, 2} = \frac{- 5 \pm 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 97}{2 \cdot 1}, x_{2} = \frac{- 5 - 97}{2 \cdot 1}

x = \frac{- 5 + 97}{2 \cdot 1} : \frac{- 5 + 97}{2}

x = \frac{- 5 - 97}{2 \cdot 1} : \frac{- 5 - 97}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 97}{2}, x = \frac{- 5 - 97}{2}

- x^{2} + 5 x + 8 = 0

c - c^{2} = \frac{1}{6}

x, 4 x y + x^{2} - 2 y^{2} = - 2

x^{2} - 16 x + 37 = 0

9 x^{2} - 19 x + 2 = 0

What are the solutions to the equation x^2+5x-18=0 ?
The solutions to the equation x^2+5x-18=0 are x=(-5+sqrt(97))/2 ,x=(-5-sqrt(97))/2
Find the zeros of x^2+5x-18=0
The zeros of x^2+5x-18=0 are x=(-5+sqrt(97))/2 ,x=(-5-sqrt(97))/2