What are the solutions to the equation m^2+27=-12m ?

The solutions to the equation m^2+27=-12m are m=-3,m=-9

Find the zeros of m^2+27=-12m

The zeros of m^2+27=-12m are m=-3,m=-9

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m^{2} + 27 = - 12 m

m = - 3, m = - 9

Solution steps

m^{2} + 27 = - 12 m

Move

12 m

to the left side

m^{2} + 27 + 12 m = 0

Write in the standard form

a x^{2} + b x + c = 0

m^{2} + 12 m + 27 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 27 = 6

m_{1, 2} = \frac{- 12 \pm 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 12 + 6}{2 \cdot 1}, m_{2} = \frac{- 12 - 6}{2 \cdot 1}

m = \frac{- 12 + 6}{2 \cdot 1} : - 3

m = \frac{- 12 - 6}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

m = - 3, m = - 9

x^{2} + 6 x - 1 = 0

x, 2 x^{2} + 4 x y + 2 y^{2} - 5 x + 4 y + 7 = 0

x (12 - x) = 2 x^{2} - 8

16 y^{2} - 361 = 0

(x + 4) (x - 5) + 3 = 0

What are the solutions to the equation m^2+27=-12m ?
The solutions to the equation m^2+27=-12m are m=-3,m=-9
Find the zeros of m^2+27=-12m
The zeros of m^2+27=-12m are m=-3,m=-9