What are the solutions to the equation z^2-8z+25=0 ?

The solutions to the equation z^2-8z+25=0 are z=4+3i,z=4-3i

Find the zeros of z^2-8z+25=0

The zeros of z^2-8z+25=0 are z=4+3i,z=4-3i

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z^{2} - 8 z + 25 = 0

z = 4 + 3 i, z = 4 - 3 i

Solution steps

z^{2} - 8 z + 25 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 25 : 6 i

z_{1, 2} = \frac{- ( - 8 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 8 ) + 6 i}{2 \cdot 1}, z_{2} = \frac{- ( - 8 ) - 6 i}{2 \cdot 1}

z = \frac{- ( - 8 ) + 6 i}{2 \cdot 1} : 4 + 3 i

z = \frac{- ( - 8 ) - 6 i}{2 \cdot 1} : 4 - 3 i

The solutions to the quadratic equation are:

z = 4 + 3 i, z = 4 - 3 i

2 f (0) = x^{2} - 3

4 x^{2} - 20 x + 28 = 3

x^{2} + 3 x + 2 x = 0

- 4 x^{2} - 7 x = 0

- 2 x^{2} + 25 = 0

What are the solutions to the equation z^2-8z+25=0 ?
The solutions to the equation z^2-8z+25=0 are z=4+3i,z=4-3i
Find the zeros of z^2-8z+25=0
The zeros of z^2-8z+25=0 are z=4+3i,z=4-3i