What are the solutions to the equation 2f(0)=x^2-3 ?

The solutions to the equation 2f(0)=x^2-3 are x=sqrt(2f(0)+3),x=-sqrt(2f(0)+3)

Find the zeros of 2f(0)=x^2-3

The zeros of 2f(0)=x^2-3 are x=sqrt(2f(0)+3),x=-sqrt(2f(0)+3)

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2 f (0) = x^{2} - 3

x = 2 f (0) + 3, x = - 2 f (0) + 3

Solution steps

2 f (0) = x^{2} - 3

Switch sides

x^{2} - 3 = 2 f (0)

Move

3

to the right side

x^{2} = 2 f (0) + 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2 f (0) + 3, x = - 2 f (0) + 3

4 x^{2} - 20 x + 28 = 3

x^{2} + 3 x + 2 x = 0

- 4 x^{2} - 7 x = 0

- 2 x^{2} + 25 = 0

(5 x - 15) (3 x + 12) = 0

What are the solutions to the equation 2f(0)=x^2-3 ?
The solutions to the equation 2f(0)=x^2-3 are x=sqrt(2f(0)+3),x=-sqrt(2f(0)+3)
Find the zeros of 2f(0)=x^2-3
The zeros of 2f(0)=x^2-3 are x=sqrt(2f(0)+3),x=-sqrt(2f(0)+3)