What are the solutions to the equation (5x-15)(3x+12)=0 ?

The solutions to the equation (5x-15)(3x+12)=0 are x=3,x=-4

Find the zeros of (5x-15)(3x+12)=0

The zeros of (5x-15)(3x+12)=0 are x=3,x=-4

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(5 x - 15) (3 x + 12) = 0

x = 3, x = - 4

Solution steps

(5 x - 15) (3 x + 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 15 = 0 or 3 x + 12 = 0

Solve

5 x - 15 = 0 : x = 3

Solve

3 x + 12 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

2 x (x + 2) = 3

2 x^{2} - 4 x = 3 x + 4

4 c^{2} + 10 c^{2} = 29 + 1

2 x^{2} + 5 x = 2

10 x^{2} + x - 1 = 0

What are the solutions to the equation (5x-15)(3x+12)=0 ?
The solutions to the equation (5x-15)(3x+12)=0 are x=3,x=-4
Find the zeros of (5x-15)(3x+12)=0
The zeros of (5x-15)(3x+12)=0 are x=3,x=-4