What are the solutions to the equation 4c^2+10c^2=29+1 ?

The solutions to the equation 4c^2+10c^2=29+1 are c=sqrt(15/7),c=-sqrt(15/7)

Find the zeros of 4c^2+10c^2=29+1

The zeros of 4c^2+10c^2=29+1 are c=sqrt(15/7),c=-sqrt(15/7)

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4 c^{2} + 10 c^{2} = 29 + 1

c = \frac{15}{7}, c = - \frac{15}{7}

Decimal Notation

c = 1.46385 \dots, c = - 1.46385 \dots

Solution steps

4 c^{2} + 10 c^{2} = 29 + 1

Add similar elements:

4 c^{2} + 10 c^{2} = 14 c^{2}

14 c^{2} = 29 + 1

Add the numbers:

29 + 1 = 30

14 c^{2} = 30

Divide both sides by

14

c^{2} = \frac{15}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = \frac{15}{7}, c = - \frac{15}{7}

2 x^{2} + 5 x = 2

10 x^{2} + x - 1 = 0

3 y^{2} - 108 = 0

x, z = \frac{( x ^{2} - y ^{2} )}{2}

2 x^{2} + x = 4 x - 2

What are the solutions to the equation 4c^2+10c^2=29+1 ?
The solutions to the equation 4c^2+10c^2=29+1 are c=sqrt(15/7),c=-sqrt(15/7)
Find the zeros of 4c^2+10c^2=29+1
The zeros of 4c^2+10c^2=29+1 are c=sqrt(15/7),c=-sqrt(15/7)