What are the solutions to the equation (x+8)(x-6)=627 ?

The solutions to the equation (x+8)(x-6)=627 are x=25,x=-27

Find the zeros of (x+8)(x-6)=627

The zeros of (x+8)(x-6)=627 are x=25,x=-27

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(x + 8) (x - 6) = 627

x = 25, x = - 27

Solution steps

(x + 8) (x - 6) = 627

Expand

(x + 8) (x - 6) : x^{2} + 2 x - 48

x^{2} + 2 x - 48 = 627

Move

627

to the left side

x^{2} + 2 x - 675 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 675 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 675) = 52

x_{1, 2} = \frac{- 2 \pm 52}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 52}{2 \cdot 1}, x_{2} = \frac{- 2 - 52}{2 \cdot 1}

x = \frac{- 2 + 52}{2 \cdot 1} : 25

x = \frac{- 2 - 52}{2 \cdot 1} : - 27

The solutions to the quadratic equation are:

x = 25, x = - 27

x^{2} + 10 x + 22 = 0

3^{2} = 2^{2} + b^{2}

- 0.6 (x - 2.5)^{2} + 8.75 = 0

p^{2} - p - 1 = 0

- 55 = - 4 x^{2} + 6 x - 1

What are the solutions to the equation (x+8)(x-6)=627 ?
The solutions to the equation (x+8)(x-6)=627 are x=25,x=-27
Find the zeros of (x+8)(x-6)=627
The zeros of (x+8)(x-6)=627 are x=25,x=-27