What are the solutions to the equation 2c*2c-2c=12 ?

The solutions to the equation 2c*2c-2c=12 are c=2,c=-3/2

Find the zeros of 2c*2c-2c=12

The zeros of 2c*2c-2c=12 are c=2,c=-3/2

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2 c \cdot 2 c - 2 c = 12

c = 2, c = - \frac{3}{2}

Decimal Notation

c = 2, c = - 1.5

Solution steps

2 c \cdot 2 c - 2 c = 12

Expand

2 c \cdot 2 c - 2 c : 4 c^{2} - 2 c

4 c^{2} - 2 c = 12

Move

12

to the left side

4 c^{2} - 2 c - 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 12) = 14

c_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 \cdot 4}

Separate the solutions

c_{1} = \frac{- ( - 2 ) + 14}{2 \cdot 4}, c_{2} = \frac{- ( - 2 ) - 14}{2 \cdot 4}

c = \frac{- ( - 2 ) + 14}{2 \cdot 4} : 2

c = \frac{- ( - 2 ) - 14}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

c = 2, c = - \frac{3}{2}

\frac{x ^{2}}{10} - \frac{3 x}{4} = x

25 n^{2} - 15 n + 4 = 5 n

3^{2} + x^{2} = 9^{2}

x^{2} - \frac{1}{16} = 4

4 x^{2} - 36 x = - 81

What are the solutions to the equation 2c*2c-2c=12 ?
The solutions to the equation 2c*2c-2c=12 are c=2,c=-3/2
Find the zeros of 2c*2c-2c=12
The zeros of 2c*2c-2c=12 are c=2,c=-3/2