What are the solutions to the equation 4x^2-36x=-81 ?

The solutions to the equation 4x^2-36x=-81 are x= 9/2

Find the zeros of 4x^2-36x=-81

The zeros of 4x^2-36x=-81 are x= 9/2

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4 x^{2} - 36 x = - 81

x = \frac{9}{2}

Decimal Notation

x = 4.5

Solution steps

4 x^{2} - 36 x = - 81

Move

81

to the left side

4 x^{2} - 36 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 81}{2 \cdot 4}

(- 36)^{2} - 4 \cdot 4 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 36 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 36 )}{2 \cdot 4}

\frac{- ( - 36 )}{2 \cdot 4} = \frac{9}{2}

x = \frac{9}{2}

The solution to the quadratic equation is:

x = \frac{9}{2}

4 x^{2} - 37 x + 52 = - 8 x + 7

2 (s^{2} + 5 s + 6) = 0

x^{2} - 36 = - 9 x

0.3 + 0.08 x - 0.0012 x^{2} = 0

x (x + 6) + 2 x (x + 4) = x^{2} + 8

What are the solutions to the equation 4x^2-36x=-81 ?
The solutions to the equation 4x^2-36x=-81 are x= 9/2
Find the zeros of 4x^2-36x=-81
The zeros of 4x^2-36x=-81 are x= 9/2