What are the solutions to the equation x^2-2sqrt(3)x+4=0 ?

The solutions to the equation x^2-2sqrt(3)x+4=0 are x=sqrt(3)+i,x=sqrt(3)-i

Find the zeros of x^2-2sqrt(3)x+4=0

The zeros of x^2-2sqrt(3)x+4=0 are x=sqrt(3)+i,x=sqrt(3)-i

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x^{2} - 23 x + 4 = 0

x = 3 + i, x = 3 - i

Solution steps

x^{2} - 23 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 3 ) \pm ( - 2 3 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 23)^{2} - 4 \cdot 1 \cdot 4 : 2 i

x_{1, 2} = \frac{- ( - 2 3 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 3 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 3 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 2 3 ) + 2 i}{2 \cdot 1} : 3 + i

x = \frac{- ( - 2 3 ) - 2 i}{2 \cdot 1} : 3 - i

The solutions to the quadratic equation are:

x = 3 + i, x = 3 - i

8 x - 3 = 2 x^{2} + 3

- 2 x^{2} - x + 11 = 0

4 x^{2} = 2 (x + 1)

x, x^{2} y^{2} - 2 x y - 6 = 0

x^{2} - x - 30 = 15 - x^{2}

What are the solutions to the equation x^2-2sqrt(3)x+4=0 ?
The solutions to the equation x^2-2sqrt(3)x+4=0 are x=sqrt(3)+i,x=sqrt(3)-i
Find the zeros of x^2-2sqrt(3)x+4=0
The zeros of x^2-2sqrt(3)x+4=0 are x=sqrt(3)+i,x=sqrt(3)-i