What are the solutions to the equation -2x^2-x+11=0 ?

The solutions to the equation -2x^2-x+11=0 are x=-(1+sqrt(89))/4 ,x=(sqrt(89)-1)/4

Find the zeros of -2x^2-x+11=0

The zeros of -2x^2-x+11=0 are x=-(1+sqrt(89))/4 ,x=(sqrt(89)-1)/4

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- 2 x^{2} - x + 11 = 0

x = - \frac{1 + 89}{4}, x = \frac{89 - 1}{4}

Decimal

x = - 2.60849 \dots, x = 2.10849 \dots

Solution steps

- 2 x^{2} - x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 11}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 11 = 89

x_{1, 2} = \frac{- ( - 1 ) \pm 89}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 89}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 89}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 89}{2 ( - 2 )} : - \frac{1 + 89}{4}

x = \frac{- ( - 1 ) - 89}{2 ( - 2 )} : \frac{89 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 89}{4}, x = \frac{89 - 1}{4}

4 x^{2} = 2 (x + 1)

x, x^{2} y^{2} - 2 x y - 6 = 0

x^{2} - x - 30 = 15 - x^{2}

n^{2} + 16 n + 5 = 25

4 x^{2} - 4 x - 48 = 0

What are the solutions to the equation -2x^2-x+11=0 ?
The solutions to the equation -2x^2-x+11=0 are x=-(1+sqrt(89))/4 ,x=(sqrt(89)-1)/4
Find the zeros of -2x^2-x+11=0
The zeros of -2x^2-x+11=0 are x=-(1+sqrt(89))/4 ,x=(sqrt(89)-1)/4