What are the solutions to the equation n^2+16n+5=25 ?

The solutions to the equation n^2+16n+5=25 are n=2(sqrt(21)-4),n=-2(4+sqrt(21))

Find the zeros of n^2+16n+5=25

The zeros of n^2+16n+5=25 are n=2(sqrt(21)-4),n=-2(4+sqrt(21))

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n^{2} + 16 n + 5 = 25

n = 2 (21 - 4), n = - 2 (4 + 21)

Decimal Notation

n = 1.16515 \dots, n = - 17.16515 \dots

Solution steps

n^{2} + 16 n + 5 = 25

Move

25

to the left side

n^{2} + 16 n - 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 20) = 421

n_{1, 2} = \frac{- 16 \pm 4 21}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 16 + 4 21}{2 \cdot 1}, n_{2} = \frac{- 16 - 4 21}{2 \cdot 1}

n = \frac{- 16 + 4 21}{2 \cdot 1} : 2 (21 - 4)

n = \frac{- 16 - 4 21}{2 \cdot 1} : - 2 (4 + 21)

The solutions to the quadratic equation are:

n = 2 (21 - 4), n = - 2 (4 + 21)

4 x^{2} - 4 x - 48 = 0

\frac{1}{2} X - \frac{X - 2}{4} = \frac{1}{2} (X \cdot \frac{2 X - 1}{3})

x^{2} - \frac{5}{2} x = - \frac{3}{2}

4 (x + 1)^{2} = 100

4 p^{2} + 4 p + 1 = 0

What are the solutions to the equation n^2+16n+5=25 ?
The solutions to the equation n^2+16n+5=25 are n=2(sqrt(21)-4),n=-2(4+sqrt(21))
Find the zeros of n^2+16n+5=25
The zeros of n^2+16n+5=25 are n=2(sqrt(21)-4),n=-2(4+sqrt(21))