What are the solutions to the equation 3x^2=40 ?

The solutions to the equation 3x^2=40 are x=(2sqrt(10))/(sqrt(3)),x=-(2sqrt(10))/(sqrt(3))

Find the zeros of 3x^2=40

The zeros of 3x^2=40 are x=(2sqrt(10))/(sqrt(3)),x=-(2sqrt(10))/(sqrt(3))

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3 x^{2} = 40

x = \frac{2 10}{3}, x = - \frac{2 10}{3}

Decimal Notation

x = 3.65148 \dots, x = - 3.65148 \dots

Solution steps

3 x^{2} = 40

Divide both sides by

3

x^{2} = \frac{40}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{40}{3}, x = - \frac{40}{3}

\frac{40}{3} = \frac{2 10}{3}

- \frac{40}{3} = - \frac{2 10}{3}

x = \frac{2 10}{3}, x = - \frac{2 10}{3}

4 x^{2} = - 12 x - 5

x^{2} - 3 (2 x + 1) = 0

x^{2} + 2 x - 5 = 2

3902850 x^{2} - 6615000 x + 615475 = 0

3 x^{2} + 75 x = 0

What are the solutions to the equation 3x^2=40 ?
The solutions to the equation 3x^2=40 are x=(2sqrt(10))/(sqrt(3)),x=-(2sqrt(10))/(sqrt(3))
Find the zeros of 3x^2=40
The zeros of 3x^2=40 are x=(2sqrt(10))/(sqrt(3)),x=-(2sqrt(10))/(sqrt(3))