What are the solutions to the equation 5x^2+2x+9=0 ?

The solutions to the equation 5x^2+2x+9=0 are x=-1/5+i(2sqrt(11))/5 ,x=-1/5-i(2sqrt(11))/5

Find the zeros of 5x^2+2x+9=0

The zeros of 5x^2+2x+9=0 are x=-1/5+i(2sqrt(11))/5 ,x=-1/5-i(2sqrt(11))/5

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5 x^{2} + 2 x + 9 = 0

x = - \frac{1}{5} + i \frac{2 11}{5}, x = - \frac{1}{5} - i \frac{2 11}{5}

Solution steps

5 x^{2} + 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 \cdot 9}{2 \cdot 5}

Simplify

2^{2} - 4 \cdot 5 \cdot 9 : 411 i

x_{1, 2} = \frac{- 2 \pm 4 11 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 4 11 i}{2 \cdot 5}, x_{2} = \frac{- 2 - 4 11 i}{2 \cdot 5}

x = \frac{- 2 + 4 11 i}{2 \cdot 5} : - \frac{1}{5} + i \frac{2 11}{5}

x = \frac{- 2 - 4 11 i}{2 \cdot 5} : - \frac{1}{5} - i \frac{2 11}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{5} + i \frac{2 11}{5}, x = - \frac{1}{5} - i \frac{2 11}{5}

4 z = 77 - z^{2}

x^{2} + (x - 5)^{2} = (x + 5)^{2}

229 = 5 \cdot \frac{x ^{2}}{3}

x (x + 14) = - 48

4^{2} + 1 0^{2} = c^{2}

What are the solutions to the equation 5x^2+2x+9=0 ?
The solutions to the equation 5x^2+2x+9=0 are x=-1/5+i(2sqrt(11))/5 ,x=-1/5-i(2sqrt(11))/5
Find the zeros of 5x^2+2x+9=0
The zeros of 5x^2+2x+9=0 are x=-1/5+i(2sqrt(11))/5 ,x=-1/5-i(2sqrt(11))/5