What are the solutions to the equation pi(x+2)^2=16pi ?

The solutions to the equation pi(x+2)^2=16pi are x=-6,x=2

Find the zeros of pi(x+2)^2=16pi

The zeros of pi(x+2)^2=16pi are x=-6,x=2

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π (x + 2)^{2} = 16 π

x = - 6, x = 2

Solution steps

π (x + 2)^{2} = 16 π

Move

16 π

to the left side

π (x + 2)^{2} - 16 π = 0

Factor

π (x + 2)^{2} - 16 π : π (x + 6) (x - 2)

π (x + 6) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or x - 2 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - 6, x = 2

3 t^{2} - 10 t = 8

x^{2} - 12 x = 61

5 z - 2 (z^{2} + 1) = 0

z^{2} - 4 z + 4

x, \frac{x ^{2}}{1.62} = 5.56 \cdot 1 0^{- 10}

What are the solutions to the equation pi(x+2)^2=16pi ?
The solutions to the equation pi(x+2)^2=16pi are x=-6,x=2
Find the zeros of pi(x+2)^2=16pi
The zeros of pi(x+2)^2=16pi are x=-6,x=2