What are the solutions to the equation -3x^2+6x+1=0 ?

The solutions to the equation -3x^2+6x+1=0 are x=-(-3+2sqrt(3))/3 ,x=(3+2sqrt(3))/3

Find the zeros of -3x^2+6x+1=0

The zeros of -3x^2+6x+1=0 are x=-(-3+2sqrt(3))/3 ,x=(3+2sqrt(3))/3

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- 3 x^{2} + 6 x + 1 = 0

x = - \frac{- 3 + 2 3}{3}, x = \frac{3 + 2 3}{3}

Decimal Notation

x = - 0.15470 \dots, x = 2.15470 \dots

Solution steps

- 3 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 1 = 43

x_{1, 2} = \frac{- 6 \pm 4 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 4 3}{2 ( - 3 )}, x_{2} = \frac{- 6 - 4 3}{2 ( - 3 )}

x = \frac{- 6 + 4 3}{2 ( - 3 )} : - \frac{- 3 + 2 3}{3}

x = \frac{- 6 - 4 3}{2 ( - 3 )} : \frac{3 + 2 3}{3}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 2 3}{3}, x = \frac{3 + 2 3}{3}

- 2 y^{2} + 30 y = 0

- x^{2} + 4 x = - 12

C (t) = - 0.0002 t^{2} + 0.06 t, 0 \leq t \leq 240

110.25 - 17.5 y + 7 y^{2} = 120

x, x^{2} + 4 y^{2} + z^{2} = 9

What are the solutions to the equation -3x^2+6x+1=0 ?
The solutions to the equation -3x^2+6x+1=0 are x=-(-3+2sqrt(3))/3 ,x=(3+2sqrt(3))/3
Find the zeros of -3x^2+6x+1=0
The zeros of -3x^2+6x+1=0 are x=-(-3+2sqrt(3))/3 ,x=(3+2sqrt(3))/3