What are the solutions to the equation X^2-3(2X-5)=10 ?

The solutions to the equation X^2-3(2X-5)=10 are X=5,X=1

Find the zeros of X^2-3(2X-5)=10

The zeros of X^2-3(2X-5)=10 are X=5,X=1

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X^{2} - 3 (2 X - 5) = 10

X = 5, X = 1

Solution steps

X^{2} - 3 (2 X - 5) = 10

Expand

X^{2} - 3 (2 X - 5) : X^{2} - 6 X + 15

X^{2} - 6 X + 15 = 10

Move

10

to the left side

X^{2} - 6 X + 5 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

X_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, X_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

X = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

X = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

X = 5, X = 1

n^{2} = 20 - n

x, x^{2} + p x + 12 = 0

x^{2} - \frac{81}{4} = 0

t, - \frac{1}{2} \cdot g \cdot t^{2} + v \cdot t = 0

x^{2} - 12 x + 36 = x

What are the solutions to the equation X^2-3(2X-5)=10 ?
The solutions to the equation X^2-3(2X-5)=10 are X=5,X=1
Find the zeros of X^2-3(2X-5)=10
The zeros of X^2-3(2X-5)=10 are X=5,X=1