What are the solutions to the equation (x-3)^2+(x-3)^2=25 ?

The solutions to the equation (x-3)^2+(x-3)^2=25 are x= 5/(sqrt(2))+3,x=-5/(sqrt(2))+3

Find the zeros of (x-3)^2+(x-3)^2=25

The zeros of (x-3)^2+(x-3)^2=25 are x= 5/(sqrt(2))+3,x=-5/(sqrt(2))+3

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(x - 3)^{2} + (x - 3)^{2} = 25

x = \frac{5}{2} + 3, x = - \frac{5}{2} + 3

Decimal Notation

x = 6.53553 \dots, x = - 0.53553 \dots

Solution steps

(x - 3)^{2} + (x - 3)^{2} = 25

Add similar elements:

(x - 3)^{2} + (x - 3)^{2} = 2 (x - 3)^{2}

2 (x - 3)^{2} = 25

Divide both sides by

2

(x - 3)^{2} = \frac{25}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = \frac{25}{2} : x = \frac{5}{2} + 3

Solve

x - 3 = - \frac{25}{2} : x = - \frac{5}{2} + 3

The solutions to the quadratic equation are:

x = \frac{5}{2} + 3, x = - \frac{5}{2} + 3

9 m^{2} - 12 m - 2 = 0

6^{2} + b^{2} = 1 1^{2}

- 6 x^{2} + x + 35 = 0

7 x^{2} - x - 66 = 0

400 - x^{2} = \frac{x}{60} + 5

What are the solutions to the equation (x-3)^2+(x-3)^2=25 ?
The solutions to the equation (x-3)^2+(x-3)^2=25 are x= 5/(sqrt(2))+3,x=-5/(sqrt(2))+3
Find the zeros of (x-3)^2+(x-3)^2=25
The zeros of (x-3)^2+(x-3)^2=25 are x= 5/(sqrt(2))+3,x=-5/(sqrt(2))+3