What are the solutions to the equation 6^2+b^2=11^2 ?

The solutions to the equation 6^2+b^2=11^2 are b=sqrt(85),b=-sqrt(85)

Find the zeros of 6^2+b^2=11^2

The zeros of 6^2+b^2=11^2 are b=sqrt(85),b=-sqrt(85)

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6^{2} + b^{2} = 1 1^{2}

b = 85, b = - 85

Decimal Notation

b = 9.21954 \dots, b = - 9.21954 \dots

Solution steps

6^{2} + b^{2} = 1 1^{2}

Move

6^{2}

to the right side

b^{2} = 85

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 85, b = - 85

- 6 x^{2} + x + 35 = 0

7 x^{2} - x - 66 = 0

400 - x^{2} = \frac{x}{60} + 5

s^{2} + 2 s + 6 = 0

x^{2} + 8 x - 1 = 0

What are the solutions to the equation 6^2+b^2=11^2 ?
The solutions to the equation 6^2+b^2=11^2 are b=sqrt(85),b=-sqrt(85)
Find the zeros of 6^2+b^2=11^2
The zeros of 6^2+b^2=11^2 are b=sqrt(85),b=-sqrt(85)