What are the solutions to the equation r^2-18r+97=0 ?

The solutions to the equation r^2-18r+97=0 are r=9+4i,r=9-4i

Find the zeros of r^2-18r+97=0

The zeros of r^2-18r+97=0 are r=9+4i,r=9-4i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 18 r + 97 = 0

r = 9 + 4 i, r = 9 - 4 i

Solution steps

r^{2} - 18 r + 97 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 97}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 97 : 8 i

r_{1, 2} = \frac{- ( - 18 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 18 ) + 8 i}{2 \cdot 1}, r_{2} = \frac{- ( - 18 ) - 8 i}{2 \cdot 1}

r = \frac{- ( - 18 ) + 8 i}{2 \cdot 1} : 9 + 4 i

r = \frac{- ( - 18 ) - 8 i}{2 \cdot 1} : 9 - 4 i

The solutions to the quadratic equation are:

r = 9 + 4 i, r = 9 - 4 i

12 x^{2} + 1 = - 7 x

3 x^{2} - 6 x = 65

x, x^{2} y - 12 = 0

- 3 c^{2} + 3 c = c - 3

x^{2} - \frac{26 x}{5} - \frac{24}{5} = 0

What are the solutions to the equation r^2-18r+97=0 ?
The solutions to the equation r^2-18r+97=0 are r=9+4i,r=9-4i
Find the zeros of r^2-18r+97=0
The zeros of r^2-18r+97=0 are r=9+4i,r=9-4i