What are the solutions to the equation -3c^2+3c=c-3 ?

The solutions to the equation -3c^2+3c=c-3 are c=-(-1+sqrt(10))/3 ,c=(1+sqrt(10))/3

Find the zeros of -3c^2+3c=c-3

The zeros of -3c^2+3c=c-3 are c=-(-1+sqrt(10))/3 ,c=(1+sqrt(10))/3

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- 3 c^{2} + 3 c = c - 3

c = - \frac{- 1 + 10}{3}, c = \frac{1 + 10}{3}

Decimal Notation

c = - 0.72075 \dots, c = 1.38742 \dots

Solution steps

- 3 c^{2} + 3 c = c - 3

Move

3

to the left side

- 3 c^{2} + 3 c + 3 = c

Move

c

to the left side

- 3 c^{2} + 2 c + 3 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) \cdot 3}{2 ( - 3 )}

2^{2} - 4 (- 3) \cdot 3 = 210

c_{1, 2} = \frac{- 2 \pm 2 10}{2 ( - 3 )}

Separate the solutions

c_{1} = \frac{- 2 + 2 10}{2 ( - 3 )}, c_{2} = \frac{- 2 - 2 10}{2 ( - 3 )}

c = \frac{- 2 + 2 10}{2 ( - 3 )} : - \frac{- 1 + 10}{3}

c = \frac{- 2 - 2 10}{2 ( - 3 )} : \frac{1 + 10}{3}

The solutions to the quadratic equation are:

c = - \frac{- 1 + 10}{3}, c = \frac{1 + 10}{3}

x^{2} - \frac{26 x}{5} - \frac{24}{5} = 0

7 a^{2} - 29 a - 30 = 0

200 = \frac{2}{125} t^{2} - \frac{16}{5} t + 320

6 x^{2} - x^{2} + 2 x = x

P^{2} = 2.97370166 \cdot 1 0^{- 19} \cdot 149597870700 0^{3}

What are the solutions to the equation -3c^2+3c=c-3 ?
The solutions to the equation -3c^2+3c=c-3 are c=-(-1+sqrt(10))/3 ,c=(1+sqrt(10))/3
Find the zeros of -3c^2+3c=c-3
The zeros of -3c^2+3c=c-3 are c=-(-1+sqrt(10))/3 ,c=(1+sqrt(10))/3