What are the solutions to the equation factor 15x^2+2x-8=0 ?

The solutions to the equation factor 15x^2+2x-8=0 are x= 2/3 ,x=-4/5

Find the zeros of factor 15x^2+2x-8=0

The zeros of factor 15x^2+2x-8=0 are x= 2/3 ,x=-4/5

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15 x^{2} + 2 x - 8 = 0

x = \frac{2}{3}, x = - \frac{4}{5}

Decimal Notation

x = 0.66666 \dots, x = - 0.8

Solution steps

15 x^{2} + 2 x - 8 = 0

Factor

15 x^{2} + 2 x - 8 : (3 x - 2) (5 x + 4)

(3 x - 2) (5 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 5 x + 4 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

5 x + 4 = 0 : x = - \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{4}{5}

1 - 0.6 x - 0.27 x^{2} = 0

50 + t^{2} = 200 + 5 t

(x^{2}) (3) = 114

- 4.91 (\frac{10 982}{491} - x)^{2} + 1.6 = 0

2 u^{2} + 4 u + 9 = (u - 1)^{2}

What are the solutions to the equation factor 15x^2+2x-8=0 ?
The solutions to the equation factor 15x^2+2x-8=0 are x= 2/3 ,x=-4/5
Find the zeros of factor 15x^2+2x-8=0
The zeros of factor 15x^2+2x-8=0 are x= 2/3 ,x=-4/5