What are the solutions to the equation x^2+4^2=25 ?

The solutions to the equation x^2+4^2=25 are x=3,x=-3

Find the zeros of x^2+4^2=25

The zeros of x^2+4^2=25 are x=3,x=-3

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x^{2} + 4^{2} = 25

x = 3, x = - 3

Solution steps

x^{2} + 4^{2} = 25

Move

4^{2}

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

x^{2} - 4 x - 32 = 0

4 (x + 5)^{2} - 7 (x + 2)^{2} = 6 x

- 4 k^{2} - 8 k - 3 = - 3 - 5 k^{2}

x^{2} + 3 x - 1 = - x + 4

0 = - 16 t^{2} + 128 t + 144

What are the solutions to the equation x^2+4^2=25 ?
The solutions to the equation x^2+4^2=25 are x=3,x=-3
Find the zeros of x^2+4^2=25
The zeros of x^2+4^2=25 are x=3,x=-3