What are the solutions to the equation 4x+x^2+4=0 ?

The solutions to the equation 4x+x^2+4=0 are x=-2

Find the zeros of 4x+x^2+4=0

The zeros of 4x+x^2+4=0 are x=-2

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4 x + x^{2} + 4 = 0

x = - 2

Solution steps

4 x + x^{2} + 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

6 x^{2} + 16 x = 0

- 16 t^{2} + 112 t - 160 = 0

x^{2} + 5 x - 19 = 0

4 x^{2} - 7 x + 9 = 0

- 2 (x - 4)^{2} + 50 = 0

What are the solutions to the equation 4x+x^2+4=0 ?
The solutions to the equation 4x+x^2+4=0 are x=-2
Find the zeros of 4x+x^2+4=0
The zeros of 4x+x^2+4=0 are x=-2