What are the solutions to the equation 5x^2-12x-18=0 ?

The solutions to the equation 5x^2-12x-18=0 are x=(3(2+sqrt(14)))/5 ,x=(3(2-sqrt(14)))/5

Find the zeros of 5x^2-12x-18=0

The zeros of 5x^2-12x-18=0 are x=(3(2+sqrt(14)))/5 ,x=(3(2-sqrt(14)))/5

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5 x^{2} - 12 x - 18 = 0

x = \frac{3 ( 2 + 14 )}{5}, x = \frac{3 ( 2 - 14 )}{5}

Decimal Notation

x = 3.44499 \dots, x = - 1.04499 \dots

Solution steps

5 x^{2} - 12 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 5 ( - 18 )}{2 \cdot 5}

(- 12)^{2} - 4 \cdot 5 (- 18) = 614

x_{1, 2} = \frac{- ( - 12 ) \pm 6 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 14}{2 \cdot 5}, x_{2} = \frac{- ( - 12 ) - 6 14}{2 \cdot 5}

x = \frac{- ( - 12 ) + 6 14}{2 \cdot 5} : \frac{3 ( 2 + 14 )}{5}

x = \frac{- ( - 12 ) - 6 14}{2 \cdot 5} : \frac{3 ( 2 - 14 )}{5}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 + 14 )}{5}, x = \frac{3 ( 2 - 14 )}{5}

2 x^{2} - 3 = 13

12 x^{2} - 196 x + 468 = 0

x, x^{2} + 2 y^{2} - 2 x + 8 + 5 = 0

x^{2} = \frac{4}{81}

x, z^{2} = 4 - x^{2} - y^{2}

What are the solutions to the equation 5x^2-12x-18=0 ?
The solutions to the equation 5x^2-12x-18=0 are x=(3(2+sqrt(14)))/5 ,x=(3(2-sqrt(14)))/5
Find the zeros of 5x^2-12x-18=0
The zeros of 5x^2-12x-18=0 are x=(3(2+sqrt(14)))/5 ,x=(3(2-sqrt(14)))/5