What are the solutions to the equation x^2+(8x)/3-1=0 ?

The solutions to the equation x^2+(8x)/3-1=0 are x= 1/3 ,x=-3

Find the zeros of x^2+(8x)/3-1=0

The zeros of x^2+(8x)/3-1=0 are x= 1/3 ,x=-3

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x^{2} + \frac{8 x}{3} - 1 = 0

x = \frac{1}{3}, x = - 3

Decimal Notation

x = 0.33333 \dots, x = - 3

Solution steps

x^{2} + \frac{8 x}{3} - 1 = 0

Multiply both sides by

3

3 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 3) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 3}, x_{2} = \frac{- 8 - 10}{2 \cdot 3}

x = \frac{- 8 + 10}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 8 - 10}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 3

t^{2} - t - 6 = - 6

t, \frac{b ^{2}}{2} - \frac{t ^{2}}{8} = 1

0 = 4 x - x^{2} - x^{2}

20.13 = - 4.9 t^{2} + 15.3 t + 28.32

x, f = 4 x^{2} - 5 f (5)

What are the solutions to the equation x^2+(8x)/3-1=0 ?
The solutions to the equation x^2+(8x)/3-1=0 are x= 1/3 ,x=-3
Find the zeros of x^2+(8x)/3-1=0
The zeros of x^2+(8x)/3-1=0 are x= 1/3 ,x=-3