What are the solutions to the equation 5x^2+9x+1=0 ?

The solutions to the equation 5x^2+9x+1=0 are x=(-9+sqrt(61))/(10),x=(-9-sqrt(61))/(10)

Find the zeros of 5x^2+9x+1=0

The zeros of 5x^2+9x+1=0 are x=(-9+sqrt(61))/(10),x=(-9-sqrt(61))/(10)

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5 x^{2} + 9 x + 1 = 0

x = \frac{- 9 + 61}{10}, x = \frac{- 9 - 61}{10}

Decimal Notation

x = - 0.11897 \dots, x = - 1.68102 \dots

Solution steps

5 x^{2} + 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 1 = 61

x_{1, 2} = \frac{- 9 \pm 61}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 61}{2 \cdot 5}, x_{2} = \frac{- 9 - 61}{2 \cdot 5}

x = \frac{- 9 + 61}{2 \cdot 5} : \frac{- 9 + 61}{10}

x = \frac{- 9 - 61}{2 \cdot 5} : \frac{- 9 - 61}{10}

The solutions to the quadratic equation are:

x = \frac{- 9 + 61}{10}, x = \frac{- 9 - 61}{10}

(- 1 - x) (3 - x) = 0

2 s^{2} + 4 s + 2 = 0

3 c^{2} - 2 c - 4 = \frac{( - 1 ) - ( - 1 )}{( 2 ) - ( - 2 )}

3 x^{2} + 18 x + 15 = 0

x, x^{2} - 6 x + 1 = 0

What are the solutions to the equation 5x^2+9x+1=0 ?
The solutions to the equation 5x^2+9x+1=0 are x=(-9+sqrt(61))/(10),x=(-9-sqrt(61))/(10)
Find the zeros of 5x^2+9x+1=0
The zeros of 5x^2+9x+1=0 are x=(-9+sqrt(61))/(10),x=(-9-sqrt(61))/(10)