What are the solutions to the equation 4x^2-56x+196=0 ?

The solutions to the equation 4x^2-56x+196=0 are x=7

Find the zeros of 4x^2-56x+196=0

The zeros of 4x^2-56x+196=0 are x=7

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4 x^{2} - 56 x + 196 = 0

x = 7

Solution steps

4 x^{2} - 56 x + 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 56 ) \pm ( - 56 ) ^{2} - 4 \cdot 4 \cdot 196}{2 \cdot 4}

(- 56)^{2} - 4 \cdot 4 \cdot 196 = 0

x_{1, 2} = \frac{- ( - 56 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 56 )}{2 \cdot 4}

\frac{- ( - 56 )}{2 \cdot 4} = 7

x = 7

The solution to the quadratic equation is:

x = 7

x, 4 x^{2} - 9 y^{2} = 2 x y^{2} + 3 x^{2} y - 1

x, y^{2} + x^{2} = r^{2}

\frac{7}{3} x + \frac{7}{3} = x^{2} + \frac{4}{3} x + \frac{1}{3}

8 x^{2} + 2 = 0

- x^{2} - 6.6 \cdot 1 0^{- 5} x + 6.6 \cdot 1 0^{- 5} = 0

What are the solutions to the equation 4x^2-56x+196=0 ?
The solutions to the equation 4x^2-56x+196=0 are x=7
Find the zeros of 4x^2-56x+196=0
The zeros of 4x^2-56x+196=0 are x=7