What are the solutions to the equation 3-x^2+2x=0 ?

The solutions to the equation 3-x^2+2x=0 are x=-1,x=3

Find the zeros of 3-x^2+2x=0

The zeros of 3-x^2+2x=0 are x=-1,x=3

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3 - x^{2} + 2 x = 0

x = - 1, x = 3

Solution steps

3 - x^{2} + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 3 = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 ( - 1 )}, x_{2} = \frac{- 2 - 4}{2 ( - 1 )}

x = \frac{- 2 + 4}{2 ( - 1 )} : - 1

x = \frac{- 2 - 4}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = - 1, x = 3

\frac{1}{3} h^{2} + \frac{2}{9} h = - \frac{5}{18} h - \frac{7}{3} h^{2}

x^{2} - 26 x + 160 = 0

x, x^{2} + y^{2} + 8 x + 20 = 0

3 (2 + 3 x)^{2} - 9 (2 + 3 x) = 0

(2 + t)^{2} + (9 + t)^{2} = 169

What are the solutions to the equation 3-x^2+2x=0 ?
The solutions to the equation 3-x^2+2x=0 are x=-1,x=3
Find the zeros of 3-x^2+2x=0
The zeros of 3-x^2+2x=0 are x=-1,x=3