What are the solutions to the equation (3x-1)(2x+3)=0 ?

The solutions to the equation (3x-1)(2x+3)=0 are x= 1/3 ,x=-3/2

Find the zeros of (3x-1)(2x+3)=0

The zeros of (3x-1)(2x+3)=0 are x= 1/3 ,x=-3/2

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(3 x - 1) (2 x + 3) = 0

x = \frac{1}{3}, x = - \frac{3}{2}

Decimal

x = 0.33333 \dots, x = - 1.5

Solution steps

(3 x - 1) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or 2 x + 3 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{2}

2 x^{2} - 5 x - 3 = 4

x^{2} + 9 = 0

3 x^{2} - 25 x + 3 = - 6 x - 3

6 x^{2} - 8 = 4 x^{2} + 7 x

2 x^{2} + (8 - 2 n) x + 11 = 0

What are the solutions to the equation (3x-1)(2x+3)=0 ?
The solutions to the equation (3x-1)(2x+3)=0 are x= 1/3 ,x=-3/2
Find the zeros of (3x-1)(2x+3)=0
The zeros of (3x-1)(2x+3)=0 are x= 1/3 ,x=-3/2