What are the solutions to the equation 4x^2-12x+12=0 ?

The solutions to the equation 4x^2-12x+12=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2

Find the zeros of 4x^2-12x+12=0

The zeros of 4x^2-12x+12=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2

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4 x^{2} - 12 x + 12 = 0

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

Solution steps

4 x^{2} - 12 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

Simplify

(- 12)^{2} - 4 \cdot 4 \cdot 12 : 43 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 3 i}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 3 i}{2 \cdot 4} : \frac{3}{2} + i \frac{3}{2}

x = \frac{- ( - 12 ) - 4 3 i}{2 \cdot 4} : \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

4.9 t^{2} - 78.4 t + 73.5 = 0

0 = 2 x^{2} - 6 x + 2, x

(1 - x) (- 1 - x) + 2 = 0

(3 z - 4) (3 z + 4) = 0

(x 2 + 2 x - 2) \cdot (m x - n) = 5 x 3 + 8 x 2 - 14 x + 4

What are the solutions to the equation 4x^2-12x+12=0 ?
The solutions to the equation 4x^2-12x+12=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2
Find the zeros of 4x^2-12x+12=0
The zeros of 4x^2-12x+12=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2