What are the solutions to the equation 1-1/6 x-1/3 x^2=0 ?

The solutions to the equation 1-1/6 x-1/3 x^2=0 are x=-2,x= 3/2

Find the zeros of 1-1/6 x-1/3 x^2=0

The zeros of 1-1/6 x-1/3 x^2=0 are x=-2,x= 3/2

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1 - \frac{1}{6} x - \frac{1}{3} x^{2} = 0

x = - 2, x = \frac{3}{2}

Decimal Notation

x = - 2, x = 1.5

Solution steps

1 - \frac{1}{6} x - \frac{1}{3} x^{2} = 0

Find Least Common Multiplier of

6, 3 : 6

Multiply by LCM=

6

1 \cdot 6 - \frac{1}{6} x \cdot 6 - \frac{1}{3} x^{2} \cdot 6 = 0 \cdot 6

Simplify

- 2 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 6 = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 7}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 7}{2 ( - 2 )} : - 2

x = \frac{- ( - 1 ) - 7}{2 ( - 2 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - 2, x = \frac{3}{2}

- 3 x^{2} + 14 x - 12 = 0

2 x^{2} + 2 x - 14 = 10

50 (z + 1)^{2} + 25 z = 121 - 41 (z - 1)^{2}

d, \frac{3 ( x - 5 )}{x - 4} = u n d e f in e d

x^{2} + 16 x + 51 = 0

What are the solutions to the equation 1-1/6 x-1/3 x^2=0 ?
The solutions to the equation 1-1/6 x-1/3 x^2=0 are x=-2,x= 3/2
Find the zeros of 1-1/6 x-1/3 x^2=0
The zeros of 1-1/6 x-1/3 x^2=0 are x=-2,x= 3/2