What are the solutions to the equation 12x^2+29x+14=0 ?

The solutions to the equation 12x^2+29x+14=0 are x=-2/3 ,x=-7/4

Find the zeros of 12x^2+29x+14=0

The zeros of 12x^2+29x+14=0 are x=-2/3 ,x=-7/4

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12 x^{2} + 29 x + 14 = 0

x = - \frac{2}{3}, x = - \frac{7}{4}

Decimal Notation

x = - 0.66666 \dots, x = - 1.75

Solution steps

12 x^{2} + 29 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 12 \cdot 14}{2 \cdot 12}

2 9^{2} - 4 \cdot 12 \cdot 14 = 13

x_{1, 2} = \frac{- 29 \pm 13}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 29 + 13}{2 \cdot 12}, x_{2} = \frac{- 29 - 13}{2 \cdot 12}

x = \frac{- 29 + 13}{2 \cdot 12} : - \frac{2}{3}

x = \frac{- 29 - 13}{2 \cdot 12} : - \frac{7}{4}

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - \frac{7}{4}

x, (x + 3)^{2} + (y + 5)^{2} + (z - 1)^{2} = 4

x (x + 2) = 2

y^{2} - 2 y - 3 = y - 3

x^{2} + 3 x - 36 = 0

(4 x - 3) (x + 1) = 0

What are the solutions to the equation 12x^2+29x+14=0 ?
The solutions to the equation 12x^2+29x+14=0 are x=-2/3 ,x=-7/4
Find the zeros of 12x^2+29x+14=0
The zeros of 12x^2+29x+14=0 are x=-2/3 ,x=-7/4