What are the solutions to the equation (2x-1)(x+3)=-5 ?

The solutions to the equation (2x-1)(x+3)=-5 are x=-1/2 ,x=-2

Find the zeros of (2x-1)(x+3)=-5

The zeros of (2x-1)(x+3)=-5 are x=-1/2 ,x=-2

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(2 x - 1) (x + 3) = - 5

x = - \frac{1}{2}, x = - 2

Decimal Notation

x = - 0.5, x = - 2

Solution steps

(2 x - 1) (x + 3) = - 5

Expand

(2 x - 1) (x + 3) : 2 x^{2} + 5 x - 3

2 x^{2} + 5 x - 3 = - 5

Move

5

to the left side

2 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 2}, x_{2} = \frac{- 5 - 3}{2 \cdot 2}

x = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 2

a + 3 = 30 a^{2}

z^{2} - 8 z + 80 = 0

x, 17 x^{2} \cdot 2 y^{2} + z^{2} - 8 x y - 6 x z - 2 = 0

x^{2} - 16 x + 36 = 0

3 x^{2} - 5 x + 1 = 0

What are the solutions to the equation (2x-1)(x+3)=-5 ?
The solutions to the equation (2x-1)(x+3)=-5 are x=-1/2 ,x=-2
Find the zeros of (2x-1)(x+3)=-5
The zeros of (2x-1)(x+3)=-5 are x=-1/2 ,x=-2