What are the solutions to the equation x^2-16x+36=0 ?

The solutions to the equation x^2-16x+36=0 are x=2(4+sqrt(7)),x=2(4-sqrt(7))

Find the zeros of x^2-16x+36=0

The zeros of x^2-16x+36=0 are x=2(4+sqrt(7)),x=2(4-sqrt(7))

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x^{2} - 16 x + 36 = 0

x = 2 (4 + 7), x = 2 (4 - 7)

Decimal Notation

x = 13.29150 \dots, x = 2.70849 \dots

Solution steps

x^{2} - 16 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 36 = 47

x_{1, 2} = \frac{- ( - 16 ) \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 7}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 7}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 7}{2 \cdot 1} : 2 (4 + 7)

x = \frac{- ( - 16 ) - 4 7}{2 \cdot 1} : 2 (4 - 7)

The solutions to the quadratic equation are:

x = 2 (4 + 7), x = 2 (4 - 7)

3 x^{2} - 5 x + 1 = 0

6 x^{2} - 14 x = 0

0.6 x^{2} + 5 x - 0.6 = 0

10 x^{2} + x - 24 = 0

2 x^{2} - 5 x - 20 = 0

What are the solutions to the equation x^2-16x+36=0 ?
The solutions to the equation x^2-16x+36=0 are x=2(4+sqrt(7)),x=2(4-sqrt(7))
Find the zeros of x^2-16x+36=0
The zeros of x^2-16x+36=0 are x=2(4+sqrt(7)),x=2(4-sqrt(7))