What are the solutions to the equation 2x^2-16=4x ?

The solutions to the equation 2x^2-16=4x are x=4,x=-2

Find the zeros of 2x^2-16=4x

The zeros of 2x^2-16=4x are x=4,x=-2

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2 x^{2} - 16 = 4 x

x = 4, x = - 2

Solution steps

2 x^{2} - 16 = 4 x

Move

4 x

to the left side

2 x^{2} - 16 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 4 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 16 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 16) = 12

x_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 2}

x = \frac{- ( - 4 ) + 12}{2 \cdot 2} : 4

x = \frac{- ( - 4 ) - 12}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

4 x^{2} + 5 x = - 9

(x + 6)^{2} - 6 = 0

2 x^{2} + 10 x = 28

\frac{y ^{2} - 6}{2} = y + 1

0.1 x^{2} - 30 x + 1890 = 0

What are the solutions to the equation 2x^2-16=4x ?
The solutions to the equation 2x^2-16=4x are x=4,x=-2
Find the zeros of 2x^2-16=4x
The zeros of 2x^2-16=4x are x=4,x=-2