What are the solutions to the equation 9x^2-4x-5=0 ?

The solutions to the equation 9x^2-4x-5=0 are x=1,x=-5/9

Find the zeros of 9x^2-4x-5=0

The zeros of 9x^2-4x-5=0 are x=1,x=-5/9

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9 x^{2} - 4 x - 5 = 0

x = 1, x = - \frac{5}{9}

Decimal Notation

x = 1, x = - 0.55555 \dots

Solution steps

9 x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 9 ( - 5 )}{2 \cdot 9}

(- 4)^{2} - 4 \cdot 9 (- 5) = 14

x_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 9}, x_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 9}

x = \frac{- ( - 4 ) + 14}{2 \cdot 9} : 1

x = \frac{- ( - 4 ) - 14}{2 \cdot 9} : - \frac{5}{9}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{9}

t^{2} - 2 t (t + 1) - 8 (t + 1)^{2} = 0

y, y^{2} = \frac{x ^{3}}{2 a - x}

x^{2} = b^{2} + 2 b^{2}

x, x^{2} - 2 x y + y^{2} - 2 x - 2 y = 0

x - x^{2} = 1

What are the solutions to the equation 9x^2-4x-5=0 ?
The solutions to the equation 9x^2-4x-5=0 are x=1,x=-5/9
Find the zeros of 9x^2-4x-5=0
The zeros of 9x^2-4x-5=0 are x=1,x=-5/9