What are the solutions to the equation x^2-2/3 x+1/12 =0 ?

The solutions to the equation x^2-2/3 x+1/12 =0 are x= 1/2 ,x= 1/6

Find the zeros of x^2-2/3 x+1/12 =0

The zeros of x^2-2/3 x+1/12 =0 are x= 1/2 ,x= 1/6

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x^{2} - \frac{2}{3} x + \frac{1}{12} = 0

x = \frac{1}{2}, x = \frac{1}{6}

Decimal Notation

x = 0.5, x = 0.16666 \dots

Solution steps

x^{2} - \frac{2}{3} x + \frac{1}{12} = 0

Find Least Common Multiplier of

3, 12 : 12

Multiply by LCM=

12

x^{2} \cdot 12 - \frac{2}{3} x \cdot 12 + \frac{1}{12} \cdot 12 = 0 \cdot 12

Simplify

12 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 12 \cdot 1}{2 \cdot 12}

(- 8)^{2} - 4 \cdot 12 \cdot 1 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 12}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 12}

x = \frac{- ( - 8 ) + 4}{2 \cdot 12} : \frac{1}{2}

x = \frac{- ( - 8 ) - 4}{2 \cdot 12} : \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{1}{6}

8 x^{2} + 4 x - 4 = 0

12 x^{2} + 57 x + 45 = 0

(x + 5)^{2} = 5

0.7 x^{2} + 0.21 x - 0.03 = 0

4 (x - 9) (5 x + 1) = 0

What are the solutions to the equation x^2-2/3 x+1/12 =0 ?
The solutions to the equation x^2-2/3 x+1/12 =0 are x= 1/2 ,x= 1/6
Find the zeros of x^2-2/3 x+1/12 =0
The zeros of x^2-2/3 x+1/12 =0 are x= 1/2 ,x= 1/6